Add Two 8 Bit Numbers Code Assembly Language
Write a Program to Add Two 8 Bit Numbers in Assembly Language . Program should load data in registers AL and BL then add two Numbers .
Consider that a byte of data is present in the AL register and second byte of data is present in the BL register.
We have to add the byte in AL with the byte in BL.
- Using ADD instruction add the contents of 2 registers.
- Result will be stored in the AL register.
- Display the result using display routine.
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For example :
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AL = 09 H
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09 H
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BL = 02 H
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+
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02 H
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0B H = (11)10
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Algorithm to Add Two 8 Bit Numbers
Step 1 : Initialize the data segment.
Step 2 : Get the first number in AL register.
Step 3 : Get the second number in BL register.
Step 4 : Add the two numbers.
Step 5 : Display the result.
Step 6 : Stop
Program to Add Two 8 Bit Numbers
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.model small <br/> .data <br/> a db 09H <br/> b db 02H <br/> .code <br/> mov ax, @data ; Initialize data section <br/> mov ds, ax <br/> mov al, a ; Load number1 in al <br/> mov bl, b ; Load number2 in bl <br/> add al, bl ; add numbers and result in al <br/> mov ch, 02h ; Count of digits to be displayed <br/> mov cl, 04h ; Count to roll by 4 bits <br/> mov bh, al ; Result in reg bh <br/> l2: rol bh, cl ; roll bl so that msb comes to lsb <br/> mov dl, bh ; load dl with data to be displayed <br/> and dl, 0fH ; get only lsb <br/> cmp dl, 09 ; check if digit is 0-9 or letter A-F <br/> jbe l4 <br/> add dl, 07 ; if letter add 37H else only add 30H <br/> l4: add dl, 30H <br/> mov ah, 02 ; Function 2 under INT 21H (Display character) <br/> int 21H <br/> dec ch ; Decrement Count <br/> jnz l2 <br/> mov ah, 4CH ; Terminate Program <br/> int 21H <br/> end |
How to Run this Program :
For Running this program you should have installed Tasm on you computer . If you have not installed Tasm yet please install from Here .
C:\>tasm 8bit-add.asm
Assembling file : 8bit-add.asm
Passes : 1
Remaining memory : 438k
C:\>tlink 8bit-add.obj
C:\>8bit-add
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